Positive Orders Z(t)
For order @(@
j > 0
@)@,
suppose that @(@
H
@)@ is the same as @(@
G
@)@.
@[@
z^{(j)}
=
\frac{1}{j} \sum_{k=1}^j k x^{(k)} y^{(j-k)}
@]@
For @(@
k = 1 , \ldots , j
@)@,
the partial of @(@
H
@)@ with respect to @(@
x^{(k)}
@)@ is given by
@[@
\D{H}{ x^{(k)} }
=
\D{G}{ x^{(k)} } + \D{G}{ z^{(j)} } \D{ z^{(j)} }{ x^{(k)} }
=
\D{G}{ x^{(k)} } + \D{G}{ z^{(j)} } \frac{k}{j} y^{(j-k)}
@]@
For @(@
k = 1 , \ldots , j
@)@
The partial of @(@
H
@)@ with respect to @(@
y^{j-k}
@)@,
is given by
@[@
\D{H}{ y^{(j-k)} }
=
\D{G}{ y^{(j-k)} } + \D{G}{ z^{(j)} } \D{ z^{(j)} }{ y^{(j-k)} }
=
\D{G}{ y^{(j-k)} } + \D{G}{ z^{(j)} } \frac{k}{j} x^{k}
@]@
Order Zero Z(t)
The @(@
z^{(0)}
@)@ coefficient
is expressed as a function of the Taylor coefficients
for @(@
X(t)
@)@ and @(@
Y(t)
@)@ as follows:
In this case,
@[@
\D{H}{ x^{(0)} }
=
\D{G}{ x^{(0)} } + \D{G}{ z^{(0)} } \D{ z^{(0)} }{ x^{(0)} }
=
\D{G}{ x^{(0)} } + \D{G}{ z^{(0)} } y^{(0)}
@]@
Input File: omh/theory/erf_reverse.omh