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@(@\newcommand{\W}[1]{ \; #1 \; } \newcommand{\R}[1]{ {\rm #1} } \newcommand{\B}[1]{ {\bf #1} } \newcommand{\D}[2]{ \frac{\partial #1}{\partial #2} } \newcommand{\DD}[3]{ \frac{\partial^2 #1}{\partial #2 \partial #3} } \newcommand{\Dpow}[2]{ \frac{\partial^{#1}}{\partial {#2}^{#1}} } \newcommand{\dpow}[2]{ \frac{ {\rm d}^{#1}}{{\rm d}\, {#2}^{#1}} }@)@ This is cppad-20221105 documentation. Here is a link to its current documentation .
LuSolve With Complex Arguments: Example and Test

# include <cppad/utility/lu_solve.hpp>       // for CppAD::LuSolve
# include <cppad/utility/near_equal.hpp>     // for CppAD::NearEqual
# include <cppad/utility/vector.hpp>  // for CppAD::vector
# include <complex>               // for std::complex

typedef std::complex<double> Complex;    // define the Complex type
bool LuSolve(void)
{   bool  ok = true;
    using namespace CppAD;

    size_t   n = 3;           // number rows in A and B
    size_t   m = 2;           // number columns in B, X and S

    // A is an n by n matrix, B, X, and S are n by m matrices
    CppAD::vector<Complex> A(n * n), B(n * m), X(n * m) , S(n * m);

    Complex  logdet;          // log of determinant of A
    int      signdet;         // zero if A is singular
    Complex  det;             // determinant of A
    size_t   i, j, k;         // some temporary indices

    // set A equal to the n by n Hilbert Matrix
    for(i = 0; i < n; i++)
        for(j = 0; j < n; j++)
            A[i * n + j] = 1. / (double) (i + j + 1);

    // set S to the solution of the equation we will solve
    for(j = 0; j < n; j++)
        for(k = 0; k < m; k++)
            S[ j * m + k ] = Complex(double(j), double(j + k));

    // set B = A * S
    size_t ik;
    Complex sum;
    for(k = 0; k < m; k++)
    {   for(i = 0; i < n; i++)
        {   sum = 0.;
            for(j = 0; j < n; j++)
                sum += A[i * n + j] * S[j * m + k];
            B[i * m + k] = sum;
        }
    }

    // solve the equation A * X = B and compute determinant of A
    signdet = CppAD::LuSolve(n, m, A, B, X, logdet);
    det     = Complex( signdet ) * exp( logdet );

    double cond  = 4.62963e-4;       // condition number of A when n = 3
    double determinant = 1. / 2160.; // determinant of A when n = 3
    double delta = 1e-14 / cond;     // accuracy expected in X

    // check determinant
    ok &= CppAD::NearEqual(det, determinant, delta, delta);

    // check solution
    for(ik = 0; ik < n * m; ik++)
        ok &= CppAD::NearEqual(X[ik], S[ik], delta, delta);

    return ok;
}
Input File: example/utility/lu_solve.cpp