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z = azmul(x, y)
x
is zero and
y
is infinity,
ieee multiplication would result in not a number whereas
z
would be zero.
Base
satisfies the
base type requirements
and arguments
x
,
y
have prototypes
const Base& x
const Base& y
then the result
z
has prototype
Base z
x
,
y
have prototype
const AD<Base>& x
const AD<Base>& y
then the result
z
has prototype
AD<Base> z
x
,
y
have prototype
const VecAD<Base>::reference& x
const VecAD<Base>::reference& y
then the result
z
has prototype
AD<Base> z