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AD<Base> ay()
AD<Base> ay(x)
AD<Base>
object
ay
and initializes it as a
equal to
x
.
x
has prototype
const VecAD<Base>& x
There also is an implicit constructor where
x
has prototype
const Base& x
In this case,
ay
is a
constant parameter
x
has prototype
const Type& x
for any type that has an explicit constructor of the form
Base(x)
.
In this case,
ay
is a
constant parameter
ay
has prototype
AD<Base> ay